Right, good observation ;-) Thanks, Stefano -----Messaggio originale----- Da: shevek <[EMAIL PROTECTED]> A: [EMAIL PROTECTED] <[EMAIL PROTECTED]> Data: luned́ 22 marzo 1999 14.32 Oggetto: Re: R: LOG(x) BASIC function >On Fri, 19 Mar 1999, Stefano Fronteddu wrote: > >> Taylors rule says that >> >> log (1+x) = x - x^2/2 + x^3/3 + .... + (x^(2n+1)) / (2n+1)! >> >> so >> >> log x = (x-1) - (x-1)^2/2 + ... +(-1)^n-1 * ((x-1)^n) / n > >This is correct, but remember that this is an approximation near x=0 (in >the original form), so if you want to know log(100), it will have a large >error. For more correct values over the whole interval (you need to >specify one, preferribly not being infinitely long), there are other ways >that take longer for each step, but come much closer to the desired >function if x is large. > >Bye, >shevek > > >**** >MSX Mailinglist. To unsubscribe, send an email to [EMAIL PROTECTED] and put >in the body (not subject) "unsubscribe msx [EMAIL PROTECTED]" (without the >quotes :-) Problems? contact [EMAIL PROTECTED] (www.stack.nl/~wiebe/mailinglist/) >**** **** MSX Mailinglist. To unsubscribe, send an email to [EMAIL PROTECTED] and put in the body (not subject) "unsubscribe msx [EMAIL PROTECTED]" (without the quotes :-) Problems? contact [EMAIL PROTECTED] (www.stack.nl/~wiebe/mailinglist/) ****
