Jeff Meyer wrote:
I have the following table:
+---------+-------------+
| ID_AGE | ID_ENTRY |
+---------+-------------+
| 1 | 1 |
| 1 | 4 |
| 1 | 5 |
| 2 | 1 |
| 2 | 2 |
| 2 | 3 |
| 2 | 4 |
| 2 | 6 |
| 2 | 7 |
| 2 | 8 |
| 2 | 10 |
| 2 | 11 |
| 2 | 13 |
| 2 | 14 |
| 2 | 15 |
| 2 | 19 |
| 2 | 20 |
| 2 | 21 |
| 2 | 22 |
| 2 | 24 |
| 3 | 14 |
| 3 | 16 |
| 3 | 17 |
| 3 | 18 |
| 3 | 19 |
| 3 | 22 |
+---------+--------------+
And since INTERSECT is not currently supported how do I select the ID_ENTRY
that has both 1 and 2 for ID_AGE
SELECT ID_ENTRY WHERE ID_AGE = 1
INTERSECT
SELECT ID_ENTRY EHRE ID_AGE=2;
The results should be 1 and 4.
Thanks in advanced.
select a.id_entry from idtable a, idtable b where a.identry=b.identry
and a.age=1 and b.age=2;
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