[EMAIL PROTECTED] wrote:
Hi, while this is much faster than subquery, I found there is "cumsy" way faster than this series inner joins.
SELECT DISTINCT i.basename FROM inventory i INNER JOIN transaction t ON i.prodcode = t.prodcode AND t.date >= '2004-01-01' AND t.date <= '2004-01-31' INNER JOIN transaction tt ON i.prodcode = tt.prodcode AND tt.date >= '2005-01-01' AND tt.date <= '2005-01-31' INNER JOIN customer c ON c.custcode = t.custcode AND c.custcode = tt.custcode WHERE i.basename is not NULL and i.prodname is not NULL order by i.basename
This should give you a list of inventory basenames for all current customers (their names are still in the customer table) that "had transactions" (ordered products?) during both JAN 2004 and JAN 2005. This list will show only the products that were ordered during BOTH time periods BY THE SAME CUSTOMER at least once (at least one repeat sale, year to year, in JAN). Is this what you were after or was there a different question you were trying to answer?
I dicovered that if I create two different temporary tables with "create view as select ..." for 2 differnet period, the join between this temp tables is also much faster than this series inner joins approach. With 160000 records in the transaction table, the series inner joins takes very long time (more than 15 minutes) give out a result.
Any comment? Thanks Sam
Shawn Green
Database Administrator
Unimin Corporation - Spruce Pine
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