"Christopher Vaughan" <[EMAIL PROTECTED]> wrote on 30/03/2005 16:48:47:
> I have data in a table listed as > 44:22:22 > 333:33:33 > It stands for hhh:mm:ss > I want to break each part of the data into different parts based on > the ':' to separate them. Then I want to take that data and sum it. > I wrote an if statement to parse through this table but I can't get > it to work. I am not sure If my syntax is > wrong because I can't find anything to check against it. > > Here is the syntax: > > IF > (SELECT job_walltime > FROM time > WHERE CHAR_LENGTH( job_walltime ) >=9) > THEN > (SELECT sum( left( job_walltime, '3' ) ) hours, sum(mid( > `job_walltime` , 4, 2 )) , sum( right( job_walltime, '2' ) ) seconds > FROM `time`) > ELSE > (SELECT sum( left( job_walltime, '3' ) ) hours, sum(mid( > `job_walltime` , 3, 2 ) ), sum( right( job_walltime, '2' ) ) seconds > FROM `time`) > END > > I know this isn't the only way to do this but this but this is the > first suggestion that comes to mind. Any input would be great. IF is an operator, not a command, so it comes after the SELECT. In C terms, it is more like the "?:" operator than an "if()...else". Thus you can do SELECT x, IF (x > y, "IS BIGGER THAN", "IS SMALLER THAN"), y FROM table. -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
