The column name is Tables_in_mysql. show syntax doesn't support order
by. Information_schema tables in 5.0 do because they use the normal
select syntax.
-Eric
Jim McAtee wrote:
Hey, thanks.
show tables like 'jst%_foo'
looks like it would work just fine. Two questions:
What is the column name returned and can I do an ORDER BY? If so,
then I can just check the first and last rows in the results to
determine the numeric range.
My bad - server version is 3.23.x. Dictated by this (old as alabama)
application. They refuse to support newer versions of MySQL.
----- Original Message ----- From: "Eric Bergen" <[EMAIL PROTECTED]>
To: "Jim McAtee" <[EMAIL PROTECTED]>
Cc: <mysql@lists.mysql.com>
Sent: Monday, May 02, 2005 11:31 AM
Subject: Re: Determining if a table exists
I don't remember what commands are available in 3.21 but try these
show tables like 'table_name';
then check mysql_num_rows on the result.
describe table;
check mysql_num_rows
show tables;
then pick out the table name;
3.21 is old as alabama (forrest gump) it's time for an upgrade :)
Jim McAtee wrote:
We're running an application that creates table names in a numeric
sequence. For example:
jst0000998_foo
jst0000998_bar
jst0000999_foo
jst0000999_bar
jst0001000_foo
jst0001000_bar
jst0001001_foo
jst0001001_bar
I need to write a maintenance app that first needs to determine the
numeric range of existing tables. In the above example it would be
998 to 1001.
What would be a half-way efficient way of doing this?
MySQL version is 3.21.x, with MyISAM tables.
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
