ohh one correction: select substr(datetime,0,8) AS date, count(date) from userLog group by date;
Anoop On 5/6/05, Anoop kumar V <[EMAIL PROTECTED]> wrote: > > how about this: > > select substr(datetime,0,8) AS date, count(datetime) from userLog group by > date; > > I could not clearly understand what you wanted to average upon..... > > HTH, > Anoop > > > > On 5/6/05, Graham Anderson <[EMAIL PROTECTED]> wrote: > > > > how do I get the average number of hits per day > > > > I have a table like: > > DateTime id ip > > 20050506190723 1 121.198.262 > > > > what I have so far > > SELECT DateTime , count( * ) > > FROM userLog > > GROUP BY DateTime > > LIMIT 0 , 30 > > > > I assume that DateTime would have to be converted to a specific day > > like 2005-3-7 > > and somehow I would need to average them > > > > can a kind soul point me in the right direction > > > > g > > > > -- > > MySQL General Mailing List > > For list archives: http://lists.mysql.com/mysql > > To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] > > > > > > > -- > Thanks and best regards, > Anoop -- Thanks and best regards, Anoop
