mysql> select *,timediff(end,start) from foo;
+---------------------+---------------------+----+---------------------+
| start | end | id | timediff(end,start) |
+---------------------+---------------------+----+---------------------+
| 2005-07-14 15:00:00 | 2005-07-14 17:30:00 | 1 | 02:30:00 |
| 2005-07-14 23:00:00 | 2005-07-15 01:30:00 | 2 | 02:30:00 |
| 2005-07-14 15:00:00 | 2005-07-15 02:30:00 | 3 | 11:30:00 |
| 2005-07-14 15:00:00 | 2005-07-14 16:00:00 | 4 | 01:00:00 |
+---------------------+---------------------+----+---------------------+
On Wed, 27 Jul 2005, [iso-8859-2] Gyurasits Zolt?n wrote:
Hello All!
I would like to calculate the hour counts from 2 'datetime'.
Example: 2005-07-27 18:00 and 2005-07-27 19:30 => 1,5 hour
I try this.... but not good!
R1 : munkaido_end-munkaido_start /simple substract/
R2 : ROUND(ROUND((end-start)/10000)+
(((end-start)/1000-(ROUND((end-start)/10000)*10))/6),1) /good if is in one day/
R3 : ROUND((end-start)/10000)-76 /-76 because from 14. to 15. I don't
understand/
start end R1 R2 R3
07-14 15:00 07-14 17:30 23000 2.5 -74
07-14 23:00 07-15 01:30 783000 78.5 2
07-14 15:00 07-15 02:30 873000 87.5 11
07-14 15:00 07-14 16:00 10000 1 -75
Please help me... (exist a function for this situation?)
Tnx!
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