Bill Whitacre wrote:
printf("<tr><td> {$thearray[org]} </td>
<td align=right> {$thearray["COUNT(*)"]} </td>
<td align=right> $ {$thearray[cost]} </td></tr>");
If I replace
{$thearray[cost]}
with
number_format({$thearray[cost]}, 2)
Although this is a MySQL mailing list and your problem is not MySQL
related, but a PHP question I'll give you a brief answer.
PHP does not evaluate functions inside a double quoted string, so you
should use:
"<tr><td> ".number_format($thearray['cost'],2)." </td><td align......."
Furthermore, using $thearray[cost] is not advisable; PHP will try to
find a constant named 'cost' and if it can't find one it will use the
string itself as the value. Use a real string (quoted) instead of
relying on this feature:
$thearray['cost'] or $thearray["cost"]
Also you can use aliases in your query to avoid things like
$thearray["COUNT(*)"];
Use something like this in your query:
SELECT .... COUNT(*) AS `count` .... FROM ....
and you can use $thearray['count'] instead
As a last pointer, printf() is pretty much useless here since you don't
use any variable formatting features of printf() here. print() or echo()
are more suitable in this case.
Regards, Jigal
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