[EMAIL PROTECTED] wrote:
Claire Lee <[EMAIL PROTECTED]> wrote on 09/27/2005 03:48:11 PM:
I need to order a few names by the number following
the main name. For example swap2, swap3, swap10 in the
order of swap2, swap3, swap10, not in swap10, swap2,
swap3 as it will happen when I do an order by.
So I came up with the following query:
mysql> select distinct secname, date from optresult
where secname like 'swap%' and date like '2005-09-2%'
order by if (secname like 'swap%',(right(secname,lengt
h(secname)-locate('p',secname))+0), secname);
I was hoping it will order by the number following
each 'swap' in the secname, it doesn't work. It was
ordered instead by secname.
+----------+------------+
| secname | date |
+----------+------------+
| SWAP0.25 | 2005-09-21 |
| SWAP0.5 | 2005-09-21 |
| SWAP1 | 2005-09-21 |
| SWAP10 | 2005-09-26 |
| SWAP10 | 2005-09-23 |
| SWAP10 | 2005-09-21 |
| SWAP2 | 2005-09-26 |
| SWAP2 | 2005-09-23 |
| SWAP2 | 2005-09-22 |
| SWAP2 | 2005-09-21 |
| SWAP3 | 2005-09-21 |
| SWAP3 | 2005-09-26 |
| SWAP3 | 2005-09-23 |
| SWAP3 | 2005-09-22 |
| SWAP5 | 2005-09-21 |
| SWAP5 | 2005-09-26 |
| SWAP5 | 2005-09-23 |
| SWAP5 | 2005-09-22 |
+----------+------------+
However, if I replace the second expression in the if
statement by date, like the following, it's ordered by
date as I would expect.
mysql> select distinct secname, date from optresult
where secname like 'swap%' and date like '2005-09-2%'
order by if (secname like 'swap%',date, secname);
+----------+------------+
| secname | date |
+----------+------------+
| SWAP3 | 2005-09-21 |
| SWAP0.5 | 2005-09-21 |
| SWAP5 | 2005-09-21 |
| SWAP1 | 2005-09-21 |
| SWAP10 | 2005-09-21 |
| SWAP2 | 2005-09-21 |
| SWAP0.25 | 2005-09-21 |
| SWAP2 | 2005-09-22 |
| SWAP3 | 2005-09-22 |
| SWAP5 | 2005-09-22 |
| SWAP10 | 2005-09-23 |
| SWAP2 | 2005-09-23 |
| SWAP3 | 2005-09-23 |
| SWAP5 | 2005-09-23 |
| SWAP10 | 2005-09-26 |
| SWAP2 | 2005-09-26 |
| SWAP3 | 2005-09-26 |
| SWAP5 | 2005-09-26 |
+----------+------------+
So I tried different combinations of the second and
third expressions in the if statement in the query,
the next one is the only one I can get it to order my
way, which is not what I wanted of course since I
don't want other secnames than swap% to order this
way.
mysql> select distinct secname, date from optresult
where secname like 'swap%' and date like '2005-09-2%'
order by if (secname like 'swap%',(right(secname, leng
th(secname)-locate('p', secname))+0),
right(secname,length(secname)-locate('p',secname))+0);
+----------+------------+
| secname | date |
+----------+------------+
| SWAP0.25 | 2005-09-21 |
| SWAP0.5 | 2005-09-21 |
| SWAP1 | 2005-09-21 |
| SWAP2 | 2005-09-22 |
| SWAP2 | 2005-09-26 |
| SWAP2 | 2005-09-21 |
| SWAP2 | 2005-09-23 |
| SWAP3 | 2005-09-22 |
| SWAP3 | 2005-09-26 |
| SWAP3 | 2005-09-21 |
| SWAP3 | 2005-09-23 |
| SWAP5 | 2005-09-23 |
| SWAP5 | 2005-09-22 |
| SWAP5 | 2005-09-26 |
| SWAP5 | 2005-09-21 |
| SWAP10 | 2005-09-26 |
| SWAP10 | 2005-09-21 |
| SWAP10 | 2005-09-23 |
+----------+------------+
Can anyone see what problems I have in my query? I'm
really stuck here. Thanks.
Claire
So you want to sort by secname except when secname starts with 'SWAP'
ORDER BY secname
, if (secname like 'swap%'
,(right(secname, length(secname)-locate('p', secname))+0)
,0)
, date;
by giving every *other* entry a default second sort-by of 0, they end up
all sorting according to secname then date. It's when secname starts with
swap that you get the sub-sorting value according to the end of the
string. Make sense?
If secname is like 'swap%', why are you then using locate to find the p
when it has to be the 4th letter or secname wouldn't be like 'swap%'.
Also if your first order by argument is secname how is the second
argument going to do anything since swap10 and swap2 are different the
first argument is all you need to uniquely identify them.
--
Chris W
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