And another one is (in inverse order for laziness): select (8 & 1) AS `0` , (8 & 2 > 1) AS `1` , (8 & 4 > 1) AS `2` , (8 & 8 > 1) AS `3` , (8 & 16 > 1) AS `4` , (8 & 32 > 1) AS `5` , (8 & 64 > 1) AS `6` , (8 & 128 > 1) AS `7` ;
Ed Reed wrote: > Well I solved the problem by using LPAD but it would be nice if there was a > more elegant way of handling this problem. > > Thanks for the help. > > >>>> "Ed Reed" <[EMAIL PROTECTED]> 1/10/06 2:52 PM >>> >>>> > Thanks Gordon and Bill but this has one big problem > > If my decimal number is 8 the result ends up, > > Results: > +---+---+---+---+---+---+---+---+ > | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 | > +---+---+---+---+---+---+---+---+ > | 1 | 0 | 0 | 0 | | | | | > +---+---+---+---+---+---+---+---+ > > when what i really need is, > > Results: > +---+---+---+---+---+---+---+---+ > | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 | > +---+---+---+---+---+---+---+---+ > | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | > +---+---+---+---+---+---+---+---+ > > Any thoughts? > > > > > >>>> "Gordon Bruce" < [EMAIL PROTECTED] > 1/10/06 1:44 PM >>> >>>> > Actually CONV converts from any base to any base so if it is base 10 > then just replace the 16's with 10's. > > Too much time looking at dump's. > > -----Original Message----- > From: Bill Dodson [mailto:[EMAIL PROTECTED] > Sent: Tuesday, January 10, 2006 3:09 PM > To: Gordon Bruce > Cc: Ed Reed; mysql@lists.mysql.com > Subject: [SPAM] - Re: Converting decimal to binary - Bayesian Filter > detected spam > > If you really do mean decimal (base 10) you could use Gordon's solution > like this: > > SELECT > MID(CONV(HEX(245),16,2),1,1) AS `7`, > MID(CONV(HEX(245),16,2),2,1) AS `6`, > MID(CONV(HEX(245),16,2),3,1) AS `5`, > MID(CONV(HEX(245),16,2),4,1) AS `4`, > MID(CONV(HEX(245),16,2),5,1) AS `3`, > MID(CONV(HEX(245),16,2),6,1) AS `2`, > MID(CONV(HEX(245),16,2),7,1) AS `1`, > MID(CONV(HEX(245),16,2),8,1) AS `0` ; > > Results: > +---+---+---+---+---+---+---+---+ > | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 | > +---+---+---+---+---+---+---+---+ > | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 1 | > +---+---+---+---+---+---+---+---+ > > > Hope this helps. > > > > Gordon Bruce wrote: > > >> If by Decimal you mesn HEXIDECIMAL you can use CONV >> where the 1st arg is the HEX value, >> 2nd arg is From Base >> and 3rd arg is To Base. >> >> You will have to suround the aliases with "`'s" if you really want >> the names to be numeric. >> >> >> mysql> select MID(CONV('A5',16,2),1,1) AS `7`, >> -> MID(CONV('A5',16,2),2,1) AS `6`, >> -> MID(CONV('A5',16,2),3,1) AS `5`, >> -> MID(CONV('A5',16,2),4,1) AS `4`, >> -> MID(CONV('A5',16,2),5,1) AS `3`, >> -> MID(CONV('A5',16,2),6,1) AS `2`, >> -> MID(CONV('A5',16,2),7,1) AS `1`, >> -> MID(CONV('A5',16,2),8,1) AS `0` ; >> +---+---+---+---+---+---+---+---+ >> | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 | >> +---+---+---+---+---+---+---+---+ >> | 1 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | >> +---+---+---+---+---+---+---+---+ >> 1 row in set (0.00 sec) >> >> -----Original Message----- >> From: Ed Reed [mailto:[EMAIL PROTECTED] >> Sent: Tuesday, January 10, 2006 12:16 PM >> To: mysql@lists.mysql.com >> Subject: Converting decimal to binary >> >> Can anyone tell me if it's possible, in 4.1.11, to convert a decimal >> number to binary and have the result be returned as a separate field >> > for > >> each bit? For example, what I'd like to do is, >> >> Select ConvertToBin(245); >> >> And have a result that looked like this >> +---+---+---+---+---+---+---+---+ >> | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 | >> +---+---+---+---+---+---+---+---+ >> | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 1 | >> +---+---+---+---+---+---+---+---+ >> >> - Thanks >> >> >> >> >> >> > > > -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
