If you are looking just for duplicate (ID,vendort_no) combinations, this will find them:
SELECT ID, vendor_no, count(1) as dupes FROM table_name_here GROUP BY ID, vendor_no HAVING dupes >1; Shawn Green Database Administrator Unimin Corporation - Spruce Pine Richard Reina <[EMAIL PROTECTED]> wrote on 02/23/2006 12:49:28 PM: > I's so sorry. You are very correct. The sample data is bad. ID > should be unique. Here it is corrected. > > |ID | vendor_no | date | > |2354 | 578 | "2005-12-23"| > |2355 | 334 | "2005-12-24"| > |2356 | 339 | "2005-12-26"| > |2357 | 339 | "2005-12-26"| > |2358 | 339 | "2005-12-26"| > |2359 | 445 | "2005-12-26"| > |2360 | 522 | "2005-12-27"| > |2361 | 522 | "2005-12-27"| > > > [EMAIL PROTECTED] wrote: > I am a novice when it come to queries > such as this and was hoping > > someone could help me write a query that tells me how many records > > have the same ID and vendor number. > > > > |ID | vendor_no | date | > > |2354 | 578 | "2005-12-23"| > > |2355 | 334 | "2005-12-24"| > > |2356 | 339 | "2005-12-26"| > > |2357 | 339 | "2005-12-26"| > > |2358 | 339 | "2005-12-26"| > > |2359 | 445 | "2005-12-26"| > > |2354 | 522 | "2005-12-27"| > > |2355 | 522 | "2005-12-27"| > > > > Would I use select count? Any help would be greatly appreciated. > > I'd need a clearer spec to offer advise. What results would you want > from the example data? 2354 is there twice but with different vendor > numbers. And 522 is there twice with different IDs. One interpretation > of "[records with] the same ID and vendor number" is 0 because no record > has both the same as any other. > > > > > > A people that values its privileges above its principles soon loses both. > -Dwight D. Eisenhower.
