On Sat, 2006-03-11 at 12:53 -0500, fbsd_user wrote:
> $sql = "SELECT logon_id
> FROM members
> WHERE logon_id = '$logonid' AND logon_pw =
> '$logonpw'";
>
> $result = mysql_query($sql) or die('Query failed. ' .
> mysql_error());
>
> print "$result"; shows Resource id #3
>
> Where can I find meaning for what this means?
>
> And why does mysql_error() not contain the description of this
> error?
>
> And why was the 'or die' condition not taken?Try print($result[0]) or print($result['logon_id']); $result is a handle to the result set, not something you can print. It's the same thing as if you tried to print out the return value of mysql_connect, which should return a resource id. There wasn't an error with the query, so the or die shouldn't execute, and mysql_error should return null. -- Pat Adams Digital Darkness Promotions Check out the Dallas Music Wiki http://digitaldarkness.com/tiki
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