[EMAIL PROTECTED] wrote:
On Sun, 12 Mar 2006, Michael Stassen wrote:
[EMAIL PROTECTED] wrote:
looks a bit strange to me.
$result = mysql_query($query) or die('Query couldn\'t
executed:'.mysql_error());
please try something like this:
Why? There's nothing wrong with the above statement.
I've never seen logic like that before. It looks to me like
fbsd_user is trying to use the OR operator outside an if
statement.
Is the mentioned in the php manual somewhere Michael?
I've not tested this - but it looks like you are mixing sending the
mysql query and testing for the result of the query at the same time,
which AFAIK is not possible.
You should try it. It works just fine, and isn't the problem. The
problem is that you cannot treat the result of an UPDATE as if it were a
SELECT.
Regards
Keith Roberts
Yes, this is documented. It's also standard practice (in perl and C as well).
OR is not part of an if statement, it is a logical operator.
<http://www.php.net/manual/en/language.operators.logical.php> "A or B" has a
value, true or false, depending on the values of A and of B. In fact, if A is
true, then "A or B" is certainly true, so there's no need to look at B at all.
This short-circuit evaluation, combined with the fact that every assignment
returns the assigned value
<http://www.php.net/manual/en/language.expressions.php>, makes a statement like
this possible.
$result = mysql_query($query) or die('Query error:'.mysql_error());
First, the function mysql_query() is called. Its return value is assigned to
$result, *and* returned as the return value of the assignment operator (=). Now
we know A. If mysql_query succeeded, its return value (A) evaluates as true, so
the or operation must be true, so no need to look at B. If, on the other hand,
A is false (mysql_query failed), we must evaluate B to determine the value of
the "or" expression. Of course, to determine the value of B, we have to call
the referenced function, die().
Michael
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