At 15:56 +0200 25/4/06, Barry wrote:
And you don't see any misdone queries when you echo them, right?
Hope you checked that.
Hi Barry
I was wrong about its being a PHP issue: it's
definitely a MySQL error. I realised I hadn't
handled the error in such a way that I could see
what it was, but now I have, so...
The full query, in all its hideousness (but
prettied up a bit in the formatting :-) ) is:
----------
select count(distinct uid) as c
from aptg_guides_restricted as r, aptg_guides as g
left join guides_biography as b on b.guide_id = r.uid
left join guides_interests as i on i.guide_id = r.uid
left join guides_tours as t on t.guide_id = r.uid
left join guides_walks as w on w.guide_id = r.uid
left join guides_lectures as l on l.guide_id = r.uid
where g.guide_uid = r.uid and show_on_web = '1' and
(b.biography like '%london%' or i.interests like
'%london%' or t.tours like '%london%' or w.walks
like '%london%' or l.lectures like '%london%')
----------
and the error I get back is:
Unknown column 'r.uid' in 'on clause'
...but I can assure you there is definitely a
'uid' column in aptg_guides_restricted. If I take
out the 'r.' from those left joins (there's no
uid in any other table mentioned here) I get
basically the same error: Unknown column 'uid' in
'on clause'. And if I spell out
'aptg_guides_restricted.uid' in the joins I
/still/ get the error: Unknown column
'aptg_guides_restricted.uid' in 'on clause'
So what /is/ the problem here? I say again: this
and /exactly/ this worked perfectly in MySQL
3.23, so there's obviously some change in syntax
handling or whatever between versions.
In fact, this is a preliminary query to establish
the total. If there is a total, I then run this:
----------
select distinct uid, firstname, lastname,
year_qualified, other_qualifications,
guide_driverguide, guide_photo_1
from aptg_guides_restricted as r, aptg_guides as g
left join guides_biography as b on b.guide_id = r.uid
left join guides_interests as i on i.guide_id = r.uid
left join guides_tours as t on t.guide_id = r.uid
left join guides_walks as w on w.guide_id = r.uid
left join guides_lectures as l on l.guide_id = r.uid
where g.guide_uid = r.uid and show_on_web = '1' and
(b.biography like '%london%' or i.interests like
'%london%' or t.tours like '%london%' or w.walks
like '%london%' or l.lectures like '%london%')
order by
from_unixtime(unix_timestamp(guide_last_updated))
* (rand(1569933185) + ((length(guide_photo_1) >
1) / 3)) desc
----------
...and if I run that directly in the SQL window
in phpMyAdmin, I get the same error: Unknown
column 'r.uid' in 'on clause'.
¿Qué?
--
Cheers... Chris
Highway 57 Web Development -- http://highway57.co.uk/
I'm on a seafood diet - I see food, I eat it.
-- Dolly Parton
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