Or perhaps add a TEXT index to the table?

Peter

On 9/6/06, Philippe Poelvoorde <[EMAIL PROTECTED]> wrote:
2006/9/5, Ben Lachman <[EMAIL PROTECTED]>:
> So possibly a better solution would be to create a temporary table
> and then do a subquery on that table?

yes. Or do a :
SELECT id FROM t1 WHERE name LIKE '%s1%' OR name LIKE  %'s2%' OR name
LIKE '%s3%'
but depending on your data, a table may be the way to go.

>
> ->Ben
>
> On Sep 4, 2006, at 7:37 AM, Visolve DB Team wrote:
>
> > Hi
> >
> > The ANY keyword, which must follow a comparison operator, means
> > "return TRUE if the comparison is TRUE for ANY of the values in the
> > column that the subquery returns
> >
> > In has 2 forms:
> > 1.  IN (subquery).  [The word IN is an alias for = ANY (subquery)].
> > 2. IN (list of values seperated by comma)
> >
> > Hence the exact syntax to use is:
> > Select <fields> from < table> where <fieldname> = ANY ( select
> > <fieldname> from <table>);
> >
> > Ref: http://dev.mysql.com/doc/refman/5.0/en/any-in-some-
> > subqueries.html
> >
> > Thanks
> > ViSolve DB Team
> >
> > ----- Original Message -----
> > From: "Ben Lachman" <[EMAIL PROTECTED]>
> > To: <mysql@lists.mysql.com>
> > Sent: Sunday, September 03, 2006 10:33 AM
> > Subject: IN & ANY subqueries
> >
> >
> >> I have a string comparison that I would like to do against a short
> >> list of constant strings.
> >>
> >> at the moment I am using the syntax
> >>
> >> SELECT id FROM t1 WHERE name IN('s1', 's2', 's3', ...);
> >>
> >> However, this limits me to exact matches and I'd like to move to a
> >> caparison expersion that lets me match names that contain any of the
> >> list.  The MySQL docs state that 'IN()' is an alias to '= ANY()'
> >> however when I substitute' = ANY' for IN I get a parse error.  What
> >> I'd like to do is write something like (although I figure there may
> >> be a better way to do the comparison that I am not thinking of):
> >>
> >> SELECT id FROM t1 WHERE name LIKE ANY('%s1%', '%s2%', '%s3%', ...);
> >>
> >> Does anyone know a way to do this?
> >>
> >> Thanks,
> >>
> >> ->Ben
> >>
>
>
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>


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