I found if I divided into 2 steps, I will find the record in table B: Ta - the given timestamp from table A;
1) select min(abs(Ta - timestamp)) as min_t from B; 2) select * from B where (timestamp + min_t = Ta) or (timestamp - min_t = Ta); But, how can I make these 2 steps into 1 query? Thanks. Xiaobo > Hi, all > > The version of Mysql is 4.0.15 on Solaris 9. I am in such a situation. > There are 2 tables something like these: > > Table A: > ---------------------------------- > location|timestamp | other fields > ------------------------------- > > > Table B > > -------------------------------- > location|timestamp | other fields > --------------------------------- > > (location. timestamp) make the 'primary key' for each table. > > The task is that: the locations are the same, given a timestamp from table > A, I need to find the record in table B which has the closest timestamp as > the given one in table A. > > I checked the book and research the internet, but didn't find a hint or > solution yet. Could any one give me a hint please? > > Thanks in advance. > > Xiaobo > > > -- > MySQL General Mailing List > For list archives: http://lists.mysql.com/mysql > To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] > > -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
