This might work for you, Jerry - you're on the right track, pretty close.
SELECT prod.prod_id, COUNT(*) FROM prod, prod_rel WHERE prod.prod_id = prod_rel.prod_id GROUP BY prod.prod_id ORDER BY 2 DESC LIMIT 1 Be aware that using the LIMIT 1 may be misleading in that if you have multiple entries with the same highest number of relations, you'll only see one. That may or may not matter to you. HTH, Dan On 10/31/06, Jerry Schwartz <[EMAIL PROTECTED]> wrote:
This should be simple, but I haven't used a subquery in quite this way, and have little experience with GROUP BY. I have 2 tables prod: prod_id /* a unique key */ prod_rel: prod_id /* values that tie prod_rel to prod */ A prod_id in prod might have 0 or more matching rows in prod_rel. I want to find the prod_id of the entry in prod that has the most dependent rows in prod_rel, and how many dependent rows it has. SELECT MAX(c) FROM (SELECT COUNT(prod_rel.prod_id) AS c FROM prod, prod_rel WHERE prod.prod_id = prod_rel.prod_id GROUP BY prod_rel.prod_id) AS t1; gives me +--------+ | MAX(c) | +--------+ | 7 | +--------+ That's all fine and dandy, but I haven't figured out how to get the actual value of prod_id that goes with that maximum value. I tried mysql> SELECT MAX(c), id FROM -> (SELECT COUNT(prod_rel.prod_id) as c, prod_rel.prod_id as id -> FROM prod, prod_rel -> WHERE prod.prod_id = prod_rel.prod_id GROUP BY prod_rel.prod_id) -> AS t; and got ERROR 1140 (42000): Mixing of GROUP columns (MIN(),MAX(),COUNT(),...) with no GROUP columns is illegal if there is no GROUP BY clause I had a feeling that I couldn't just use id in the outer select, but how do I get it? I tried adding GROUP BY t.prod_id, but that just gave me the same error. Please help me find my way. Regards, Jerry Schwartz Global Information Incorporated 195 Farmington Ave. Farmington, CT 06032 860.674.8796 / FAX: 860.674.8341 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
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