No, this won't work I actually have a table of support ticket records record_id ticket_id date name status department_id and other columns
I must select an ordered list of ticket_id where each row is the most recent record of gived ticket: max(record_id) for given ticket_id I currently solved this using two queries: First will select a list of max record_id's: SELECT MAX(record_id) GROUP BY ticket_id Then using API I create a comma separated list of record_id's. Then I select the latest records of each ticket: SELECT * WHERE record_id IN (........) I just wonder if there is more optimised solution Thanks a lot ----- Original Message ---- From: Tim Lucia <[EMAIL PROTECTED]> To: mysql@lists.mysql.com Sent: Saturday, November 11, 2006 3:56:49 PM Subject: RE: MAX() and GROUP BY question How about select ID, X, Y, Z from USERS order by ID desc limit 1 Tim -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Friday, November 10, 2006 5:47 PM To: mysql@lists.mysql.com Subject: MAX() and GROUP BY question Hello everybody Can you explain me please how to get the entire row where ID is maximum per given status_id Mysql 4.0.xx for example: id status_id name date 6 3 name0 date0 5 1 name1 date1 7 4 name3 date3 10 3 name2 date2 If I execute SELECT MAX(id), status, name, date FROM table_name WHERE status=3 GROUP BY staus_id or SELECT MAX(id), status, name, date GROUP BY staus_id only id and status_id will be returned correctly, while name and date can well be from another row for example: 10 3 name0 date0 Thanks a lot for any suggestions Yannis -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
