How about this:
select s.* from store s
where s.id not in
(select t.storeid from trans t where t.created=date(now()));
--
Later
Mogens Melander
+45 40 85 71 38
+66 870 133 224
On Sat, April 14, 2007 00:22, Jay Blanchard wrote:
> Good day gurus and gurettes!
>
> I have a table;
>
> | transactionid | int(11) | NO | PRI | | auto_increment |
> | username | varchar(32) | NO | | | |
> | storeid | varchar(6) | NO | | | |
> | action | int(4) | NO | | | |
> | code | int(2) | NO | | | |
> | ipAddr | varchar(32) | NO | | | |
> | created | datetime | NO | MUL | | |
> | created_by | varchar(32) | NO | | | |
>
> I used to have a query (I have misplaced it somehow) where I could tell
> which storied had not logged in (created) today yet. No matter how hard
> I try I cannot remember the query.
>
> What I need is a query that will tell me at any given point during the
> day which storeid is not online (created). I do have a sister table
> where all of the storeid's are, so the join happens there. I can test
> created for IS NULL but it does not limit the query to today.
>
> select store.storeid, store.stName
> from store left outer join transaction
> on(store.storeid = transaction.storeid)
> where transaction.created IS NULL
> and store.active = 'yes'
> group by store.storeid;
>
> How can I limit this to today only without having to hard code a date
> into the query?
>
> TVMIA!
>
> --
> MySQL General Mailing List
> For list archives: http://lists.mysql.com/mysql
> To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
>
>
> --
> This message has been scanned for viruses and
> dangerous content by OpenProtect(http://www.openprotect.com), and is
> believed to be clean.
>
>
--
This message has been scanned for viruses and
dangerous content by OpenProtect(http://www.openprotect.com), and is
believed to be clean.
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
