would you can post the table script?? create and insert...
because it should be work ...
Jason Pruim escreveu:
I have tried %jason%, %jason, & jason% all with the same result... Do
you need to have an index of the column? Currently I didn't
intentionally make one so I'm not sure if it's automatic or not...
On May 25, 2007, at 1:26 PM, Mike Lockhart wrote:
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Have you tried using 'jason%' instead of '%jason%'? Also, do you have
an index on that column?
Jason Pruim wrote:
Hi all,
I'm new to the list so please excuse me if I make some newbie mistakes,
I am having trouble figuring out why a select statement won't work,
Here's the statement: "SELECT 'FName' FROM `current` WHERE `FName` like
'%jason%';".
if I run select 'FName' FROM current; then I get 6 rows that say
'jason'. but nothing is showing up when I use 'like'.
Any ideas?
Thanks for looking!
- --
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Mike Lockhart Information Engineer
ChoiceMed, Inc
Email: [EMAIL PROTECTED]
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