Papalagi Pakeha schrieb:
> Hello,
>
> I have a query like:
> SELECT id, start_date FROM iddt WHERE id IN ('109k7','s3x6','sxmns','wt57');
> which gives me:
> +-------+---------------------+
> | id | start_date |
> +-------+---------------------+
> | 109k7 | 2007-10-07 12:06:58 |
> | sxmns | 2007-10-06 02:17:30 |
> | wt57 | 2007-10-07 15:57:37 |
> | s3x6 | 2007-10-07 08:58:20 |
> +-------+---------------------+
>
> How can I get the results sorted by the order in which they appear in
> the ID list?
i do not fully understand ... ORDER BY `id` ... ???
what ID List?
> Indeed I could do it in the application but prefer to get
> the results in the right order from MySQL as the ID list may be long
> and I may need only first few entries cropped by LIMIT clause. Ideally
> it should ORDER BY DATE(start_date) DESC and then by the ID list. Do I
> need some sort of stored function for that?
ORDER BY DATE(`start_date`) DESC, `id`
> I.e. the ideal output would be:
> +-------+---------------------+
> | id | start_date |
> +-------+---------------------+
> | 109k7 | 2007-10-07 12:06:58 |
> | s3x6 | 2007-10-07 08:58:20 |
> | wt57 | 2007-10-07 15:57:37 |
> | sxmns | 2007-10-06 02:17:30 |
> +-------+---------------------+
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