On Jan 31, 2008 1:30 PM, Jerry Schwartz <[EMAIL PROTECTED]> wrote: > That's rather what I feared. I'm trying to avoid code, mostly because this > should be a one-off run.
If it's a one-shot deal and you don't mind it taking a little time, I think something like this would work: SELECT customers.email, COUNT(*) AS n, GROUP_CONCAT(customers.customer_id), GROUP_CONCAT(memos.memo_ids) FROM customers JOIN ( SELECT customer_id, GROUP_CONCAT(memo_id) AS memo_ids FROM memos GROUP BY customer_id ) AS memos ON (customers.customer_id = memos.customer_id) GROUP BY customers.email HAVING n > 1; - Perrin -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
