Victor,
> I beg to differ:
> mysql> select SKU, Quantity, Name, Price, p.sizes,
> p.colorsShadesNumbersShort from tem126080739853 t join products p on
> t.ProdID-p.ID <http://t.prodid-p.id/>;
...on t.ProdID-p.ID... _subtracts_ the two IDs. To match them use '='
rather than '-'.
PB
-----
Victor Subervi wrote:
On Mon, Dec 14, 2009 at 12:37 PM, Peter Brawley <peter.braw...@earthlink.net
wrote:
> ... on t.ProdID-p.ID;
Your join clause subtracts the two IDs, so it's on IDs that differ, and
apparently there aren't any.
I beg to differ:
mysql> select SKU, Quantity, Name, Price, p.sizes,
p.colorsShadesNumbersShort from tem126080739853 t join products p on
t.ProdID-p.ID <http://t.prodid-p.id/>;
Empty set (0.00 sec)
mysql> select * from tem126080739853;
+----+--------+----------+----
---------+--------------------------+
| ID | ProdID | Quantity | sizes | colorsShadesNumbersShort |
+----+--------+----------+-------------+--------------------------+
| 1 | 2 | 2 | Extra-small | navy-blue:CC7722 |
+----+--------+----------+-------------+--------------------------+
1 row in set (0.00 sec)
mysql> select SKU, Quantity, Name, Price, p.sizes,
p.colorsShadesNumbersShort from tem126080739853 t join products p on
t.ProdID-p.ID <http://t.prodid-p.id/>;
Empty set (0.03 sec)
mysql> select SKU, Quantity, Name, Price, t.sizes,
t.colorsShadesNumbersShort from tem126080739853 t join products p on
t.ProdID-p.ID <http://t.prodid-p.id/>;
Empty set (0.00 sec)
mysql> select ID, SKU, Name, Price from products;
+----+----------+-------+--------+
| ID | SKU | Name | Price |
+----+----------+-------+--------+
| 2 | prodSKU1 | name1 | 555.22 |
+----+----------+-------+--------+
1 row in set (0.00 sec)
t.ProdID == 2
p.ID == 2
That's a match.
So why does my select join fail?
TIA,
V
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