SELECT
unix_timestamp() + 86400 + (unix_timestamp() % 86400);
currently gives me 6:39 AM tomorrow....
SELECT
UNIX_TIMESTAMP(DATE(FROM_UNIXTIME(1299003702)));
actually gives me what I want, but seems really stupid way of getting
something that is probably very simple
On 03/01/2011 12:03 PM, Singer X.J. Wang wrote:
http://en.wikipedia.org/wiki/Midnight
On Tue, Mar 1, 2011 at 13:00, Singer X.J. Wang <w...@singerwang.com
<mailto:w...@singerwang.com>> wrote:
That's cause there's two midnights.. use
= 1298999201 + 86400 + (1298999201 % 86400)
On Tue, Mar 1, 2011 at 12:58, Bryan Cantwell
<bcantw...@firescope.com <mailto:bcantw...@firescope.com>> wrote:
It was of course a typo, and even with the correct number
isn't the answer
On 03/01/2011 11:47 AM, Claudio Nanni wrote:
You can start by using 60*60*24=86400
;)
On Mar 1, 2011 6:17 PM, "Bryan Cantwell"
<bcantw...@firescope.com <mailto:bcantw...@firescope.com>
<mailto:bcantw...@firescope.com
<mailto:bcantw...@firescope.com>>> wrote:
> I'd asked before how to convert a unix timestamp to the
hour that it is
> in (and got the perfect answer) :
> 1298999201 = 3/1/2011 11:06:41 AM
> (1298999201 - (1298999201 % 3600)) = 3/1/2011 11:00:00 AM
>
> Now getting the timestamp converted to midnight of that
same day isn't
> as simple as:
> 1298999201 - (1298999201 % 85400)
> That just gives me a unix time from yesterday...
>
> How can I convert 1298999201 (3/1/2011 11:06:41 AM) to
1298959200
> (3/1/2011 12:00:00 AM)?
>
>
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