Exactly what you are saying Mr. Sándor. I tried adding a recordamount of debt 
then becomes a multiple of 4. Well I'm really confused. Are there any who can 
help? how to call the databaseby entering on the right?

  ----- Original Message ----- 
  From: HaidarPesebe 
  To: MySQL Lists 
  Sent: Friday, July 29, 2011 10:48 AM
  Subject: results from a total of always amount to a multiple of 3


  I experienced a unique problem, after I call the database as follows:

  SELECT id, concat(period,'-',semester) as periodsmester, sum(qty) as qtyone, 
sum(bqty) as qtytwo FROM pay a INNER JOIN debt b on (a.name=b.uname AND 
a.period=b.bperiod AND a.semester=b.bsemester) WHERE name='jon' group by 
concat(period,semester) order by period ASC, semester ASC

  but results from a total of always amount to a multiple of 3.
  should total qty (USD) pay = 8 but the result would be 24. so also for the 
Debt.

  Please help.

  Such databases

  DB 1 = pay

  id | name | period          | semester | qty(USD)
  ----------------------------------------------------------------
  1  | jon    |  2010-2011   |  1          |  2
  2  | jon    |  2010-2011   |  1          |  1
  3  | jon    |  2010-2011   |  1          |  3
  4  | jon    |  2010-2011   |  1          |  2


  DB 2 = Debt

  did | uname | bperiod        | bsemester | remark | bqty(USD)
  
---------------------------------------------------------------------------------
  1  | jon     |  2010-2011    |  1        |      paper    |   7
  2  | jon     |  2010-2011    |  1        |      mouse  |   4


  Thanks,
  Haidarpesebe


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