On Tue, Mar 27, 2012 at 3:43 PM, Dan Nelson <dnel...@allantgroup.com> wrote:
> In the last episode (Mar 27), Paul Halliday said:
>> Say I have:
>>
>> SELECT COUNT(name), name, COUNT(DISTINCT(status)) FROM table GROUP BY name
>>
>> and it returns:
>>
>> 20 paul 5
>> 19 john 2
>> 75 mark 3
>>
>> is there a way to return what comprises  DISTINCT(status) as part of the 
>> result?
>>
>> so:
>>
>> 20 paul 2,3,1,20,9
>> 19 john 20,9
>> 75 mark 1,20,9
>
> You want GROUP_CONCAT:
>

Heh, and exactly how I wanted it formatted.

Great! Thanks.

-- 
Paul Halliday
http://www.squertproject.org/

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