Hi my friends !!

Some few days i have problems with count().
i have 3 tables:

t1 holds:
+----+--------+
| id | number |
+----+--------+
|  1 | one    |
|  2 | two    |
|  3 | three  |
|  4 | four   |
|  5 | five   |
|  6 | sixs   |
+----+--------+


t2 holds:

+----+-------+---------------------+
| id   | id_t1   | t                           |
+----+-------+---------------------+
|  1  |     1    | 2001-07-03 15:03:34 |
|  2  |     1    | 2001-07-03 15:03:34 |
|  3  |     1    | 2001-07-03 15:03:34 |
|  4  |     2    | 2001-07-03 15:03:34 |
|  5  |     3    | 2001-07-04 12:00:00 |
|  6  |     3    | 2001-07-04 12:00:00 |
|  7  |     4    | 2001-07-04 13:11:00 |
+----+-------+---------------------+


t3 have it:
+----+-------+---------------------+
| id | id_t1    | t                            |
+----+-------+---------------------+
|  1 |     1    | 2001-07-04 13:11:00 |
|  2 |     2    | 2001-07-04 13:11:00 |
|  3 |     3    | 2001-07-04 13:11:00 |
|  4 |     1    | 2001-07-04 13:11:00 |
|  5 |     4    | 2001-07-04 13:11:00 |
|  6 |     4    | 2001-07-04 13:11:00 |
|  7 |     4    | 2001-07-04 13:11:00 |
+----+------+----------------------+

so, my target is: how many rows there are in table t2 and t3 coresponding to t1.
Column id_t1 in t2 and t3 are values that are present in t1.id. It is important, it 
must be one query to database.

I make this query:

select t1.id,number,count(t2.id_t1),count(t3.id_t1) from t1
left join t2 on t2.id_t1=t1.id 
left join t3 on t3.id_t1=t1.id
group by number order by number desc

But the result is not correct.

What shuld to be a query to get right result ???
i would like to have this (it is correct):

 id  | number | count(t2_id1) | count(t3_id1)|
  1 | one      |             3      |         2         |
  2 | two      |             1      |         1         |
  3 | three    |             2      |         1         |
  4 |  four     |             1      |         3         |
  5 | five      |              0      |        0          |
  6 | six        |             0       |        0         |

Does anybody help me ????

p.s; mayby that is impossible ??


Ireneusz Piasecki
webmaster www.b-c.pl
KomNet s.c
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