Christopher R. Jones writes: > Correct > The mean (average) depends on the distribution. If the distribution is > either positively or negatively skewed, then the median will not equal the > mean. The median of an ordered list is the middle value if the number of > elements is odd. If the number of elements is even, then the median is the > average of the two middle values. > >
Yes, this is correct, but it is still sampling median. On the other hand, some non-parametric test might rule out some of the values, so we are again in the beginning. -- Regards, __ ___ ___ ____ __ / |/ /_ __/ __/ __ \/ / Mr. Sinisa Milivojevic <[EMAIL PROTECTED]> / /|_/ / // /\ \/ /_/ / /__ MySQL AB, Fulltime Developer /_/ /_/\_, /___/\___\_\___/ Larnaca, Cyprus <___/ www.mysql.com --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php