I appear to be having an error with the following update that I am submitting to my database. I am using mysql's DATE_FORMAT function to pull the date out and insert in a user friendly form. Upon submission of the modified data, I use the below SQL to update the table information.
Everything is running fine when I leave out the $ShowStart and $ShowEnd out of the equation, but when I add it back in, instead of updating the existing entry in the database, it adds in a new entry. $ShowStart = ("$StartYear-$StartMonth-$StartDay"); $ShowEnd = ("$EndYear-$EndMonth-$EndDay"); $sql = mysql_query ("UPDATE tradeshows SET showname = \"$ShowName\", city = \"$ShowCity\", country = \"$ShowCountry\", startdate = \"$ShowStart\", enddate = \"$ShowEnd\", booth = \"$BoothNumber\", boothsize = \"$BoothSize\", ondisplay = \"$OnDisplay\", attendees = \"$Attendees\" WHERE ID = \"$ShowID\" "); The $ShowID variable is definitely correct, as I decided to echo it back to the browser so I could double check my PHP. I know that it is much better to use the UNIX time stamp to reformat dates, but I still do not understand what I could be doing wrong. has anyone come across this before? The MySQL version I am using is 3.23.39 (hmm. maybe I should upgrade this to start with). Cheers. Neil Silvester --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php