Hi,
Ok. Now I don't get syntax error but I don't get any results.
Anyway, I think that it is something like your examples.
Again, I need to get this results with only one query:
1st: get results from relAB to see QB relations:
SELECT B from relAB WHERE A='a1';
results:
+------+
| B |
+------+
| b1 |
| b2 |
| b3 |
+------+
(This results said that only QB b1, b2 and b3 refs are related to 'a1')
2nd: get only b1, b2, b3 from QB:
SELECT * FROM QB WHERE ref in ('b1','b2','b3');
results:
+----+------+----------+
| id | ref | question |
+----+------+----------+
| 1 | b1 | qb1 |
| 2 | b2 | qb2 |
| 3 | b3 | qb3 |
+----+------+----------+
I'm trying to adapt your examples to see if I can get it to work.
Thanks again,
Nuno Teixeira
On Sat, Feb 09, 2002 at 12:16:40PM -0500, Butch Bean wrote:
| Nuno,
|
| I think these examples will work OK for what you want...
|
| Butch
|
| SELECT QB.id, QB.ref, QB.question from QB, relAB
| WHERE QB.ref=relAB.B
| AND relAB.B='a1'
|
| SELECT DISTINCT QB.id, QB.ref, QB.question from QB, relAB
| WHERE QB.ref=relAB.B
| AND relAB.B='a1'
|
| SELECT * from QB as tbl1
| LEFT JOIN relAB as tbl2
| ON tbl2.B=tbl1.ref
| where tbl2.B='a1'
|
|
| -----Original Message-----
| From: Nuno Teixeira [mailto:[EMAIL PROTECTED]]
| Sent: Saturday, February 09, 2002 11:18 AM
| To: Butch Bean
| Cc: [EMAIL PROTECTED]
| Subject: Re: is possible 1 query with 2 selects?
|
|
|
| Hi,
|
| I try it and I get a syntax error:
|
| "You have an error in your SQL syntax near 'on tbl2.A=tbl1.A where
| tbl2.A='a1'' at line 1"
|
| My tables structure are:
|
| show fields from QB;
| +----------+-------------+------+-----+---------+----------------+
| | Field | Type | Null | Key | Default | Extra |
| +----------+-------------+------+-----+---------+----------------+
| | id | int(11) | | PRI | NULL | auto_increment |
| | ref | char(3) | YES | | NULL | |
| | question | varchar(30) | YES | | NULL | |
| +----------+-------------+------+-----+---------+----------------+
|
| show fields from relAB;
| +-------+---------+------+-----+---------+----------------+
| | Field | Type | Null | Key | Default | Extra |
| +-------+---------+------+-----+---------+----------------+
| | id | int(11) | | PRI | NULL | auto_increment |
| | A | char(3) | YES | | NULL | |
| | B | char(3) | YES | | NULL | |
| +-------+---------+------+-----+---------+----------------+
|
|
| Thanks for your help,
|
| Nuno Teixeira
|
| On Sat, Feb 09, 2002 at 08:49:44AM -0500, Butch Bean wrote:
| | I don't know you table structure but something like this would do it...
| |
| | SELECT * from QB as tbl1
| | JOIN relAB as tbl2
| | ON tbl2.A=tbl1.A
| | where tbl2.a='a1'
| |
| | Butch Bean
| |
| | -----Original Message-----
| | From: Egor Egorov [mailto:[EMAIL PROTECTED]]
| | Sent: Saturday, February 09, 2002 7:24 AM
| | To: [EMAIL PROTECTED]
| | Subject: is possible 1 query with 2 selects?
| |
| |
| | Nuno,
| |
| | Friday, February 08, 2002, 11:04:51 PM, you wrote:
| |
| |
| | NT> Hello to all,
| |
| | NT> I'm trying to make a query with only one command but I can't see how
| | to do
| | NT> it.
| |
| | [skip]
| |
| | NT> What I want to do is get a list from table QB related to an item
| from
| | NT> table QA:
| |
| | NT> For example, get a list from QB related to item 'a1':
| |
| | NT> 1. select B from relAB where A='a1';
| |
| | NT> (result: b2, b3, b4)
| |
| | NT> 2. select * from QB where ref in ('b2','b3','b4');
| |
| | NT> (result: only 'a1' related items)
| |
| | NT> There is a way of make this query with only one command?
| |
| | NT> Something like:
| |
| | NT> 1. select * from QB where ref in (select B from relAB where
| | A='a1');
| |
| | MySQL doesn't curently support sub-selects, look at:
| | http://www.mysql.com/doc/A/N/ANSI_diff_Sub-selects.html
| |
| | It is in our plans to support sub-selects in future:
| | http://www.mysql.com/doc/T/O/TODO_MySQL_4.1.html
| |
| | NT> Please help me in this matter.
| | NT> Thanks very much,
| |
| |
| |
| |
| |
| | --
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| | / |/ /_ __/ __/ __ \/ / Egor Egorov
| | / /|_/ / // /\ \/ /_/ / /__ [EMAIL PROTECTED]
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| | <___/ www.mysql.com
| |
| |
| |
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|
| --
| Nuno Teixeira
| pt-quorum.com
|
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