> select id, lname, fname, pic from database where engagedto=id; Sorry, mate, that won't work. That will find folks who are engaged to themselves, i.e., narcissists
-----Original Message----- From: Oliver Heinisch [mailto:[EMAIL PROTECTED]] Sent: Tuesday, February 19, 2002 11:30 AM To: [EMAIL PROTECTED] Subject: Re: basic query question At 19.02.2002 10:22, you wrote: >I'm fairly new to MySQL, so if anyone could help me I'd really appreciate >it! > >What I'm trying to do is join two pictures in a database to each other. My >database holds info about people with variables: > >id, lname, fname, engagedto, pic Try this, even if I´m careful due to my bad day, see todays threads ;-) select id, lname, fname, pic from database where engagedto=id; >The engagedto field contains the id of the person they are engaged to. I'm >trying to print the people that are engaged to each other next to each >other. I've played with the join command and a little with group but don't >really understand how these work... If anyone could point me in the right >direction regarding how to query the database to return these records >connected to each other, I would really appreciate it! > >Thanks so much > >Dean --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
