Hey All,
I am new to mysql and I need help debugging this peice of code for my site:
<?php
$db = mysql_connect("db30.pair.com", "net3dual", "rosevilleX1");
mysql_select_db("rahs",$db);
$search = mysql_query("SELECT * FROM rahs");
while($num=mysql_fetch_array($search)) {
printf ("<div align='center'><center><table border='0' cellpadding='0'
cellspacing='0' width=\"40%\"><tr><td
width=\"70%\">Name:%s #%s</td><td
width=\"30%\">Team: %s</td></tr><tr><td width=\"100%\" colspan='2'>Penalty:
%s</td></tr><tr><td width=\"50%\">Groundballs: %s</td><td
width=\"50%\">Shots: %s</td></tr><tr><td width=\"50%\">Faceoffs
Won:%s</td><td width=\"50%\">Faceoffs Lost: %s</td></tr><tr><td
width=\"100%\" colspan='2'><p
align='center'>Date:%s</td></tr></table></center></div>",$num["name"],$num["
number"],$num["team"],$num["penalty"],$num["groundballs"],$num["shots"],$num
["faceoffs_won"],$num["faceoffs_lost"],$num["date"]);
}
?>
it says this error:
Warning: Supplied argument is not a valid MySQL result resource on line 17
line 17 would be this line:
while($num=mysql_fetch_array($search)) {
what is wrong with my code?
Thanks!
--------------------------------------------
-Alex "Big Al" Behrens
E-mail: [EMAIL PROTECTED]
Urgent E-mail: [EMAIL PROTECTED] (Please be brief!)
Phone: 651-482-8779
Cell: 651-329-4187
Fax: 651-482-1391
ICQ: 3969599
Owner of the 3D-Unlimited Network:
http://www.3d-unlimited.com
Send News:
[EMAIL PROTECTED]
---------------------------------------------------------------------
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http://lists.mysql.com/ (the list archive)
To request this thread, e-mail <[EMAIL PROTECTED]>
To unsubscribe, e-mail <[EMAIL PROTECTED]>
Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
