On Sat, 30 Mar 2002, Paul DuBois wrote:
> At 21:25 +0100 3/30/02, Roger Baklund wrote: > >* Son Nguyen > >> ==> I tried this query, but... it's not working out: > >> SELECT YEAR(now()-birthday) from users where loginName="test"; > > > >You are very close: > > > >SELECT YEAR(now())-YEAR(birthday) as age from users where loginName="test"; > > That won't adjust for the relative difference within the calendar > year of the two dates. This works better: > > mysql> SELECT > -> YEAR(CURDATE()) - YEAR(birthday) > -> - IF(RIGHT(CURDATE(),5) < RIGHT(birthday,5),1,0) > -> AS 'age in years' > -> FROM users WHERRE loginName="test"; Or SELECT YEAR(FROM_DAYS(TO_DAYS(CURDATE()) - TO_DAYS(birthday))) AS 'age in years' FROM users WHERE loginName='test'; Michael --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php