Hi, This might work for you: select @tempvar := max(datecolumn) from tablename group by datecolumn order by datecolumn desc limit 3; select * from tablename where datecol >= @tempvar order by datecolumn desc;
Anvar. At 06:12 AM 02/05/2002 +0000, you wrote: >hi everyboby, > >How to select latest 3 days records from the table according to the >latests date. >The data is like this:- > >name date >a 02-03-01 >b 02-03-15 >c 02-03-20 >d 02-03-20 >e 02-04-28 >f 02-04-28 >g 02-04-30 > >The result should be like this:- > >name date >g 02-04-30 >f 02-04-28 >e 02-04-28 >c 02-03-20 >d 02-03-20 > > >Is it possible.Please help me. > >query,database,sql > >Thanks in advance. > > > > > > >_________________________________________________________________ >Get your FREE download of MSN Explorer at http://explorer.msn.com/intl.asp. > > >--------------------------------------------------------------------- >Before posting, please check: > http://www.mysql.com/manual.php (the manual) > http://lists.mysql.com/ (the list archive) > >To request this thread, e-mail <[EMAIL PROTECTED]> >To unsubscribe, e-mail ><[EMAIL PROTECTED]> >Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php > --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
