I have 14 fields are chars (like char(8), char(9)), and one field is int(4).
All char fields are mixed with upper case letters, numbers(0-9) and 
sign(like $).
Because there is no low case char, I don't have to put -f option for unix sort.

Thanks.

At 08:23 PM 7/23/2002 +0200, Benjamin Pflugmann wrote:
>Hi.
>
>On Thu 2002-07-11 at 09:53:05 -0400, [EMAIL PROTECTED] wrote:
> > Bhavin,
> >
> > I am using distinct all 15 fields and order by all 15 fields, but there is
> > different order on 15 fields for distinct and order by.
>
>Are all fields of binary types? If not, DISTINCT equals "sort -uf", not
>"sort -u" (i.e. ignore case) for those columns.
>
>Greetings,
>
>         Benjamin.
>
>[...]
> > >> I have a 76,500,000 rows table with 15 fields.
> > >> I try to sort this rows on all fields, so I am using select all fields1
> > >> group by  all fields2 or distinct all fields1 with order by all fields2.
> > >> After sort, I get 62,000,000 rows.
> > >>
> > >> Then I use Linux unique sort, I dump out 76,500,000 table and using
> > >sort -u
> > >> file1 -o file2.
> > >> I got 76,000,000 rows.
>
>
>--
>[EMAIL PROTECTED]


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