hi guyx

i ve a lil problem

i run this query n get a result set



$query = "SELECT lang_id,strng_id, strng FROM  strngx where pg_id = 6 and 
lang_id = '$lang_id '";
$query_result_handle = mysql_query ($query)
        or die ('qry failed !  DA tbl must xixt in DA db specifyd bov ....');

exe and store it in $row


for( $v=1; $v < mysql_num_rows($query_result_handle); $v++)
  {
     $row = mysql_fetch_row($query_result_handle);
     $str[ $row[0] ][ $row[1] ] = $row;
   }


alls well

but

i want to get a single record displayed

when i do


echo($row[2]."<br>");




i get all the records in $row[2]
but i want jst 1

what should i do ?????

how should i go about it .... ?????

plx plx help

m stuck ...
:(



thnx a million ..... billion


stuck ....

toby ....

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