Anil,
You never created a connection.
mysql_connect()
Regards.
Thursday, August 15, 2002, 1:12:21 PM, you wrote:
> Hi,
> in the piece of code given below
> -----------
> $qid = mysql_query("
> SELECT *
> FROM 1_nodedata
> WHERE id = $edit_id
> ");
> $frm = mysql_fetch_array($qid);
> -----------
> i get the follownig error:
> Warning: Supplied argument is not a valid MySQL result resource in
> /z/mercury/www/niksun/admin/add_doc.php on line 107
> element type:
> What is it happening so!!
> regards
> anil
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