Hi,
 You can try something like this :

select (CASE WHEN Data2<>141 THEN Data1 END) from your_table where Data3=1
group by Data1;

Regards,

Gelu
_____________________________________________________
G.NET SOFTWARE COMPANY

Permanent e-mail address : [EMAIL PROTECTED]
                                          [EMAIL PROTECTED]
----- Original Message -----
From: "Luc Foisy" <[EMAIL PROTECTED]>
To: "MYSQL-List (E-mail)" <[EMAIL PROTECTED]>
Sent: Monday, August 19, 2002 6:32 PM
Subject: Query Question



Some ficticious data

ID Data1 Data2 Data3
1 1 141 1
2 5 140 1
3 4 142 1
4 3 141 1
5 2 142 1
6 5 142 1
7 7 140 1
8 2 143 1
9 3 142 1
10 3 143 1
11 4 144 1
12 2 144 1
13 8 141 2
14 9 140 2
15 6 142 2
16 11 141 2
17 0 142 2
18 9 142 2
19 10 140 2
20 0 143 2
21 11 142 2
22 3 143 2
23 6 144 2
24 0 144 2

For my return I only want a single instance of "Data1", so it will most
likely need be GROUP BY Data1

I would like those records to include the "group" that does not contain a
"Data2" value of 141

There is also a WHERE clause on "Data3" = 1

The return would include these values for Data1

7
5
2
4

Is there some way to do this with a single query?

If this is unclear, let me know

Luc Foisy

Technical Magic - www.technical-magic.com
1 Stafford Road, Suite 325, Nepean, Ontario, K2H 1B9
Phone: (613) 721-8850 Fax: (613) 596-5096
E-Mail: [EMAIL PROTECTED]

<<<<< Fulfilling the Promise of Technology >>>>>


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