that would be because b.name is inside the ' ' and it is taken as a constant.
-----Original Message----- From: Jorge Martinez [mailto:[EMAIL PROTECTED]] Sent: Thursday, August 29, 2002 11:10 AM To: [EMAIL PROTECTED] Subject: like problem i need this consult select a.name from table1 a, table2 b where a.name like '%b.name%'; but i have a problem because Mysql not recognize the value of b.name --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
