Hi there! I have a question on JOINs.
First the system: table1: name: t1 entries: name field1 field2 ------------------------ test 1 2 test2 3 4 table2: name t2 entries: name field3 field4 ------------------------ test 5 6 test 7 8 table3: name t3 entries: name field5 field6 ------------------------ test 9 10 test 11 12 test2 13 14 test2 15 16 And here the problem: with the query SELECT a.*, b.*, c.* FROM t1 a INNER JOIN t2 b USING(name) INNER JOIN t3 c USING(name) WHERE b.field3=7 OR c.field6=16; I only get 1 entry with name="test". By using LEFT JOIN I only get name="test" either. For sure, because in table2 there is no test2 entry. The only 2 ways I know to get also test2: 1. "INSERT INTO t2 VALUES("test2",NULL,NULL)" 2. temporary table But I don't want to have such dummy entries or a temporary table. Does anybody know what I have to do to with: SELECT a.*,b.*,c.* FROM ?????? WHERE b.field3=5 OR c.field6=16 the result: name field1 field2 field3 field4 field5 field6 ----------------------------------------------------------------- test 1 2 5 6 9 10 test 1 2 5 6 11 12 test2 3 4 NULL NULL 15 16 I hope that someone can help me! Thank a lot, Peter ______________________________________________________________________________ WEB.DE MyPage - Ultimatives Kommunikationstool! Ihre Message sofort online! Domain aenderbar! http://www.das.ist.aber.ne.lustige.sache.ms/ --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php