At 2:40 -0800 12/28/02, Arun Kumar wrote:
But if I have varchar fields won't the size of the
record vary based on the actual contents in the
varchar fields.
Arun
Of course. My answer remains the same. Perhaps I should
add that what all this means is that you must perform
the calculations on a per-record basis, and that these
calculations, though not especially difficult, are likely
to become fairly ugly as the number of columns in your table
increase.
Don't forget that a VARCHAR containing a 10-byte
string takes a different amount of storage than, say,
a MEDIUMTEXT, TEXT, or LONGTEXT containing a 10-byte
string.
If what you really want to do (though this is *not*
what you said) is to order by the length of a given
string column, just do:
SELECT .... , LENGTH(col_name) FROM tbl_name ... ORDER BY LENGTH(col_name);
Add the appropriate constant to the LENGTH() expression to factor
in the extra number of bytes required internally to store the column
length. (E.g., 1 for VARCHAR, 4 for LONGTEXT.)
--- Paul DuBois <[EMAIL PROTECTED]> wrote:
At 18:38 -0800 12/27/02, Arun Kumar wrote:
>Dear All,
> I have a table 'X', I want to display the record
> in this table 'X' which has occupied the maximum
> number of bytes, i.e i want a query/queries to
>display the record with maximum size. I would also
>like to print the
> record size as well.
>
> Any help in this front would be great.
> Arun
You'll have to calculate record size yourself based
on knowledge
about the types of the columns in the table and the
storage occupied
> by those types.
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