PHP Guys & Dolls I have a sight display issue that I just need to resolve :)
After a select I end up with a record = 9 but I want to display the record as the name not the value. The value was inserted as a value so I need to make a join to the original table in the query, but alas I have tried a few things without any luck. So it's the experts whom I need to help out:) The query is: $result=mysql_query("SELECT items.ItemSKU, items.ItemName, items.ItemDescription, items.PostCode, items.Category, items.CityID, items.CTelephone, items.ItemID, items.Cfax, items.Cemail, items.Caddress, items.CTown, items.Cwww FROM items WHERE CityID='$CityID' ORDER BY CityID"); while ($row = mysql_fetch_row($result)) { $City=$row['5']; } the display is: <? echo "$City"; So I need to create a query that then joing the CityID from items to the CityName in table city. Or is it the php that needs to be altered? Andrew --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php