Hello, I believe, and hope, I have a very simple question, but as I am relatively new to MySQL I might be missing out on the obvious solution.
Is it possible to use a single MySQL query (with the simple scheme presented) to ask the following question? Scheme: Films (idFilm, title) Loans (idFilm, dateLoan, dateReturn, idContact, idLoan) Contacts (idContact, name) Question: What films aren’t on loan right now? Using the SQL standards it should be possible to write the following query. SELECT F.idFilm, F.title FROM Films F WHERE F.idFilm NOT IN ( SELECT L.idFilm FROM Loans L WHERE L.dateReturn IS NULL) However, this query is using a subselect, which isn’t supported by MySQL. What alternatives do I have? Knowing that it is impossible to create Views and that neither intersect nor minus (as in Oracle), are implemented, I believe the only option I am left with is using TEMPORARY TABLES. I tried to solve the problem using precisely a Temporary Table which contained the result from the subselect above. It didn’t work! The message I got was that MySQL couldn’t find the temporary table with the specified name! As one of the major goals with Database Management Systems is program-data independence I do not want to use a program-dependent solution. Additionally, I do not want to insert redundancy into the database through an extra attribute in the films table (tinyint marking 1 if a film is available, 0 if not available). What could I do to solve this simple problem? -- Remi André Mikalsen Homepage - http://mikalsen.no.sapo.pt -- Remi André Mikalsen Homepage - http://mikalsen.no.sapo.pt Email - [EMAIL PROTECTED] --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php