Fabrizio Tivano <[EMAIL PROTECTED]> wrote: > > on MySQL 3.23.54 > i have a table that list the number of user-time days like: 35 > > whell....based on curdate() function > > can i able to make a select wich display the sum (150-35) > where 150 is date_format(curdate(), '%j') > in a format like (%d/%m/%y) ? > > this kind of query is possible? > ...if yes how?
Sorry, but your explanation is not clear enough for me. You can't apply arithmetic operation directly on DATE columns, take a look at TO_DAYS() and FROM_DAYS() functions: http://www.mysql.com/doc/en/Date_and_time_functions.html -- For technical support contracts, goto https://order.mysql.com/?ref=ensita This email is sponsored by Ensita.net http://www.ensita.net/ __ ___ ___ ____ __ / |/ /_ __/ __/ __ \/ / Victoria Reznichenko / /|_/ / // /\ \/ /_/ / /__ [EMAIL PROTECTED] /_/ /_/\_, /___/\___\_\___/ MySQL AB / Ensita.net <___/ www.mysql.com -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]