Thanks for everybody's help!! This way worked for me. Clever! Chris
... and yes... even my example was messed up :-P -----Original Message----- From: Rudy Metzger [mailto:[EMAIL PROTECTED] Sent: Monday, July 14, 2003 4:15 AM To: Christopher Knight; MySQL List Subject: RE: grouping / sorting etc.. SELECT col1, IF(count(*)!=count(col2),NULL,'BAD') FROM table1 GROUP BY col1; This ONLY works EXACLTY for the case you submitted. Please note that your example is wrong (I think). 3 should also return NULL, shouldn't it? /rudy -----Original Message----- From: Christopher Knight [mailto:[EMAIL PROTECTED] Sent: vrijdag 11 juli 2003 17:32 To: MySQL List Subject: grouping / sorting etc.. Im having troubles getting the results I want... can someone suggest which way to go.. mysql 4.0 A ------------ | 1 | | | 1 | BAD | | 2 | | | 3 | BAD | | 3 | | | 4 | BAD | | 5 | | | 5 | BAD | | 5 | BAD | ------------ what I want is 5 results. If there is a NULL, then return the NULL, else return the BAD so basically return ... ------------ | 1 | | | 2 | | | 3 | BAD | | 4 | BAD | | 5 | | ------------ Ive tried select * from table group by 1stcolumn = (unpredicatble results, but returns 5 rows) select * from talbe groub by 1stcolumn, 2ndcolumn = (returns 8 rows) I could do the 2nd way then filter out w/ the code... Is there a better way? Thanks Chris -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
