Hi Many thanks to one and all for your time and assistance with my question. I used the 'AS cnt' method and it works brilliantly. Simple isn't it? :-)
Cheers Gary -----Original Message----- From: Victoria Reznichenko [mailto:[EMAIL PROTECTED] Sent: 24 July 2003 14:01 To: [EMAIL PROTECTED] Subject: Re: GROUP BY ORDER BY "Gary Broughton" <[EMAIL PROTECTED]> wrote: > > I wonder if someone could help with what I assume is a simple query > using GROUP and/or ORDER statements (something I struggle to get to > grips with). I am trying to get a list of users who have posted to a > forum by number of posts descending, but am unable to find the right > statement to do it. > > > > At the moment I have: "select count(*), user_id FROM messages WHERE > forum_id = 294 GROUP BY user_id" . which gets me what I want, but in a > random user order. > > > > I have looked through the MySQL documentation, but have been unable to > hit on the combination of functions needed to get what I need (which is > effectively 'ORDER BY count(*) DESC'). SELECT COUNT(*) AS cnt, user_id FROM messages WHERE forum_id = 294 GROUP BY user_id ORDER BY cnt DESC -- For technical support contracts, goto https://order.mysql.com/?ref=ensita This email is sponsored by Ensita.net http://www.ensita.net/ __ ___ ___ ____ __ / |/ /_ __/ __/ __ \/ / Victoria Reznichenko / /|_/ / // /\ \/ /_/ / /__ [EMAIL PROTECTED] /_/ /_/\_, /___/\___\_\___/ MySQL AB / Ensita.net <___/ www.mysql.com -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
