USE company; # SHOW INNODB STATUS;
DROP TABLE IF EXISTS DEPARTMENT; CREATE TABLE DEPARTMENT ( DNAME VARCHAR(15) NOT NULL, DNUMBER INT NOT NULL, MGRSSN CHAR(9) NOT NULL, MGRSTARTDATE DATE, PRIMARY KEY (DNUMBER), UNIQUE (DNAME), INDEX (MGRSSN), # between employee and department FOREIGN KEY (MGRSSN), # a sort of mutually declaration REFERENCES EMPLOYEE(SSN) # this is declared in employee )TYPE = INNODB; DROP TABLE IF EXISTS EMPLOYEE; CREATE TABLE EMPLOYEE ( FNAME VARCHAR(15) NOT NULL, MINIT CHAR, LNAME VARCHAR(15) NOT NULL, SSN CHAR(9) NOT NULL, BDATE DATE, ADDRESS VARCHAR(30), SEX CHAR, SALARY DECIMAL(10,2), SUPERSSN CHAR(9), DNO INT NOT NULL, PRIMARY KEY (SSN), INDEX (SUPERSSN, SSN), FOREIGN KEY (SUPERSSN) REFERENCES EMPLOYEE(SSN), INDEX (DNO, DNUMBER), FOREIGN KEY (DNO) REFERENCES DEPARTMENT(DNUMBER) # this is declared in department )TYPE = INNODB; === ERROR 1064 at line 9: You have an error in your SQL syntax. Check the manual th at corresponds to your MySQL server version for the right syntax to use near ' REFERENCES EMPLOYEE(SSN) )TYPE = INNODB' at line 10 Bye In short I have Department Dnumber References employee (ssn) Employee Ssn References department(dnumber) What can be done , please ? Yours sincerely Morten Gulbrandsen -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
