This might be a good solution. I work on it in a diferent way. I create a temporary table, insert all cod from t1, t2, t3 tables and left join it with t4 table. Not so eficient way I could say...
Anyway thanx all Nikos ----- Original Message ----- From: "Mikhail Entaltsev" <[EMAIL PROTECTED]> To: "????? ??????" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Cc: "Brent Baisley" <[EMAIL PROTECTED]> Sent: Monday, September 15, 2003 2:38 PM Subject: Re: joining 4 tables > Hi, > > You need to use UNION, but it's not possible in version 3.23.* > So it's better to upgrade MySQL server first. > > SELECT table1.cod > FROM table1 > LEFT JOIN table4 ON table1.cod=table4.cod > WHERE table4.cod IS NULL > > UNION > > SELECT table2.cod > FROM table2 > LEFT JOIN table4 ON table2.cod=table4.cod > WHERE table4.cod IS NULL > > UNION > > SELECT table3.cod > FROM table3 > LEFT JOIN table4 ON table3.cod=table4.cod > WHERE table4.cod IS NULL > > > Best regards, > Mikhail. > > ----- Original Message ----- > From: "ΝΙΚΟΣ ΓΑΤΣΗΣ" <[EMAIL PROTECTED]> > To: <[EMAIL PROTECTED]> > Cc: "Brent Baisley" <[EMAIL PROTECTED]> > Sent: Monday, September 15, 2003 1:15 PM > Subject: Re: joining 4 tables > > > Thank you all for replying. > Brent your code is nice but I'ts not what I want. > In "where" clause the equality is not true because its table has diferent > cod fields anyway. > Can you help me with that? > > > ----- Original Message ----- > From: "Brent Baisley" <[EMAIL PROTECTED]> > To: <$B&-&)&*&/&2 (B $B&#&!&3&2&'&2(B <[EMAIL PROTECTED]>)> > Cc: <[EMAIL PROTECTED]> > Sent: Friday, September 12, 2003 3:43 PM > Subject: Re: joining 4 tables > > > > SELECT table4.cod, table1.cod, table2.cod, table3.cod > > FROM table4 > > LEFT JOIN table1 ON table4.cod=table1.cod > > LEFT JOIN table1 ON table4.cod=table2.cod > > LEFT JOIN table1 ON table4.cod=table3.cod > > WHERE table1.cod IS NULL > > AND table2.cod IS NULL > > AND table3.cod IS NULL > > > > I think that should do it, I didn't test it. What you are doing is a > > left join for all the tables on table4. The left join will retain all > > the records of table4, and then you filter out any records that have no > > value in the fields for the other tables. > > > > On Friday, September 12, 2003, at 04:37 AM, $B&-&)&*&/&2(B > $B&#&!&3&2&'&2(B wrote: > > > > > Hello list > > > > > > I have a problem. I have 4 tables (in Mysql 3.23). All of them have a > > > filed > > > named cod. > > > > > > I want a query to find which cod of table1, table2, table3 is/are not > > > in > > > table4. > > > cod values in table1, table2, table3 are diferent. > > > > > > Thank you > > > Nikos > > > > > > > > > -- > > > MySQL General Mailing List > > > For list archives: http://lists.mysql.com/mysql > > > To unsubscribe: > > > http://lists.mysql.com/[EMAIL PROTECTED] > > > > > > > > -- > > Brent Baisley > > Systems Architect > > Landover Associates, Inc. > > Search & Advisory Services for Advanced Technology Environments > > p: 212.759.6400/800.759.0577 > > > -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
