Earlier I was given help understanding the need for using a left join. This was a precursory query to arrive at my final solution which I had not touched on since I believed that by getting the join correct I could get the result. It seems to be evading me though. Still using the following example table..
I have two tables. One table has entries controlnum,referencenum,fname,lname,inputtime,outputtime the second table has controlnum,referencenum. In table one referencenum can have and does have duplicates. The second table is populated with a subset of data from the first table but referencenum is unique. For instance... 1234 6666677 'bob' 'smith' '10:00:00' '11:00:00' 1234 6666677 1235 6666677 'mike' 'williams' '10:00:00' '11:00:00' 1236 5554447 1236 5554447 'debra' 'stone' '10:30:00' '11:30:00' 1238 5585888 1237 4455556 'ken' 'marwood' '11:00:00' '12:00:00' 1238 5585888 'bill' 'shireton' '11:15:00' '11:15:00' 1239 5585888 'laura' 'acree' '11:15:00' '12:15:00' 1240 5585888 'dora' 'lindsey' '11:15:00' '12:15:00' ok, now I want to run a query that results in all of the controlnum's whose reference numbers do not match the reference numbers that are linked with the controlnum's from table two together with all of the records in table two. I can't follow that description and I wrote it! Maybe an example... This is the result I want... 1234 6666677 'bob' 'smith' 1236 5554447 'debra' 'stone' 1237 4455556 'ken' 'marwood' 1238 5585888 'bill' 'shireton' So the result set does not include a record such as 1235 because it's reference number matches a reference number from a record from the same table referenced by table two. It includes all other records. Larry S. Brown Dimension Networks, Inc. (727) 723-8388 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
