Hey - Progress!  But first, I had to correct:
can't use "-p <password>", must use the longer
form: "--password=<password>"

Then I can run it!  One problem.  It deleted the
first 1000 records, rather than leaving the last
1000 records in the db.  What twist is needed to
get that right?  ?
 
--- Scott H <[EMAIL PROTECTED]> wrote:
> When I run:
> 
> mysql -p <password> -u <username> <log_db_name>
> <
> deleteold.sql
> 
> ...and within deleteold.sql, I have only this
> text (2 lines):
> 
> select (@aa:=seq) as low_seq from syslogTB
> order
> by seq limit 1000,1;
> delete from syslogTB where seq < @aa;
> 
> I just get back a screen full of syntax
> suggestions. Where is my mistake here?
> 
> --- Dan Greene wrote:
> > for example your script would be 
> > mysql --user=myuserid --password=mypassword
> -h
> > hostname < deleteold.sql
> > 
> > see:
> > http://www.mysql.com/doc/en/Batch_mode.html 
> > 
> > > -----Original Message-----
> > > From: Scott H
> > [mailto:[EMAIL PROTECTED]
> > > Sent: Wednesday, November 12, 2003 4:22 PM
> > > To: Dan Greene
> > > Cc: MySQL Mailing List
> > > Subject: RE: maintaining size of a db
> > > 
> > > 
> > > Cool idea, but I don't think you can really
> > do
> > > it. When I try, mysql just gives me back
> the
> > > syntax stuff.  <sigh>  I'm a bit perplexed
> -
> > I
> > > would have thought this would be a
> > semi-common
> > > issue in db maintenance, but no one seems
> to
> > have
> > > set this up.  I'm still trying, please send
> > any
> > > other ideas/suggestions my way...   thx!!
> > > 
> > > --- Dan Greene wrote:
> > > > you may be able to put both statements to
> a
> > > > text file, let's call it deleteold.sql
> > > > 
> > > > then your cron job would be :
> > > > 
> > > > mysql (put your connect stuff here) <
> > > > deleteold.sql
> > > > 
> > > > > From: Scott H
> > > > > Well, it sort of helps.  But that
> section
> > is
> > > > > about future enhancements intended for
> > mysql.
> > > > > I need to set something up now, with
> the
> > > > current
> > > > > stable version.  One thing I read
> (can't
> > find
> > > > it
> > > > > now) indicated that the current version
> > (I'm
> > > > > actually running 4.0.15a) has "limited"
> > > > support for subqueries - but I don't know
> 
> > > > >exactly how far that goes. 
> > > > > 
> > > > > So let me set the stage a bit more -
> I'll
> > > > assume
> > > > > for now there is no reasonably simple
> way
> > to
> > > > work
> > > > > with the actual size of the database on
> > disk,
> > > > and
> > > > > instead will go with the idea that I
> can
> > > > expect
> > > > > the size of any one record to be of
> some
> > > > average.
> > > > >  So, according to Dan's suggestion, if
> I
> > do a
> > > > > little math, and control the number of
> > > > records, I
> > > > > can control the size of the db --
> > > > approximately. 
> > > > > That's fine.  Thus if have "seq" as an
> > > > > autoincrement field, and I wanted to
> stay
> > > > around 
> > > > > say 1000 records, deleting the oldest
> > > > records, I
> > > > > would need to run a cron job that would
> > > > somehow
> > > > > nest or relate these 2 sql statements:
> > > > > 
> > > > > select (@aa:=seq) as low_seq from
> > logtable
> > > > order
> > > > > by seq limit 1000,1
> > > > > 
> > > > > delete from logtable where seq < @aa
> > > > > 
> > > > > I've tried putting this into a subquery
> > > > format
> > > > > but no luck.  But I'm a noob, so I keep
> > > > trying,
> > > > > thinking I might hit on the right
> syntax.
> > 
> > > > Or, is
> > > > > there some way to pull the value of
> > "low_seq"
> > > > > into an environment variable and use it
> > in a
> > > > > script file to run the 2nd statement? 
> > Other
> > > > > ideas?
> > > > > 
> > > > > thanks,  scott
> > > > > 
> > > > > --- Michael McTernan wrote:
> > > > > > >From the manual:
> > > > > > 
> > > > > > 1.8.4.1 Subqueries
> > > > > > 
> > > > > > Subqueries are supported in MySQL
> > version
> > > > 4.1.
> > > > > > See section 1.6.1 Features
> > > > > > Available in MySQL 4.1.
> > > > > > 
> > > > > > Hope that helps,
> > > > > > 
> > > > > > Mike
> > > > > > 
> > > > > > > From: Scott H
> > > > > > > OK, I *THINK* I follow you here. 
> > Couple
> > > > of
> > > > > > > questions.  I'm reading an online
> > > > tutorial
> > > > > > trying
> > > > > > > to figure this out, and I am led to
> > > > believe
> > > > > > mysql
> > > > > > > can't do nested queries, aka
> > sub-queries.
> > > > But
> > > > > > you
> > > > > > > say it can? Is this recent?  And I
> > don't
> > > > have
> > > > > > a
> > > > > > > timestamp field, I have an
> > autoincrement
> > > > > > field,
> > > > > > > but what do you mean by the
> > "(@aa:=id)"
> > > > > > thing?  I
> > > > > > > don't follow that.  thanks.
> > > > > > >
> > > > > > > --- Dan Greene
> > > > > > <[EMAIL PROTECTED]>
> > > > > > > wrote:
> > > > > > > > What I would do is a classical
> > > > > > guesstimate....
> > > > > > > >
> > > > > > > > find the average size per record
> > (data
> > > > file
> > > > > > > > size + index file(s) size / #
> > records
> > > > in
> > > > > > table)
> > > > > > > >
> > > > > > > > using that, find the data used
> per
> > day
> > > > > > > >
> > > > > > > > using that, figure out how many
> > days,
> > > > on
> > > > > > > > average it takes to hit 20GB
> > > > > > > >
> > > > > > > > let's say it's 89 days.
> > > > > > > >
> > > > > > > > right off the top, take 10% off
> for
> > > > safety,
> > > > > > now
> > > > > > > > we're at 80 days
> > > > > > > >
> > > > > > > > presuming your table has a
> > timestamp
> > > > field:
> > > > > > > >
> > > > > > > > delete from log_table WHERE
> > > > TO_DAYS(NOW())
> > > > > > -
> > > > > > > > TO_DAYS(date_col) > 80
> > > > > > > >
> > > > > > > > if you don't have a timestamp
> > field,
> > > > but
> > > > > > you do
> > > > > > > > have an autoincrement id field:
> > > > > > > >
> > > > > > > > figure out number of records on
> > average
> > > > =
> > > > > > 20gb
> > > > > > > > (say it's 2M)
> > > > > > > > again, use 10% for safety (1.8M)
> > > > > > > >
> > > > > > > > select (@aa:=id) as low_id from
> > > > logtable
> > > > > > order
> > > > > > > > by id limit 18000000,1
> > > > > > > > delete from logtable where id <
> @aa
> > > > > > > >
> > > > > > > > (do subqueries work with a limit
> > > > clause?)
> > > > > > > >
> > > > > > > >
> > > > > > > > > -----Original Message-----
> > > > > > > > > From: Scott H
> > > > > > > >
> [mailto:[EMAIL PROTECTED]
> > > > > > > > > Sent: Wednesday, November 12,
> > 2003
> > > > 11:19
> > > > > > AM
> > > > > > > > > To: Dan Greene; MySQL Mailing
> > List
> > > > > > > > > Subject: RE: maintaining size
> of
> > a db
> > > > > > > > >
> > > > > > > > >
> > > > > > > > > Yes sir, exactly.  It's just
> > that's
> > > > what
> > > > > > I'm
> > > > > > > > > looking for, and can't figure
> > out.  I
> > > > can
> > > > > > set
> > > > > > > > up
> > > > > > > > > a cron job, but what exactly
> > would
> > > > the
> > > > > > SQL
> > > > > > > > delete
> > > > > > > > > statement be that would allow
> me
> > to
> > > > > > delete
> > > > > > > > old
> > > > > > > > > records in such a way that the
> db
> > > > > > maintains
> > > > > > > > an
> > > > > > > > > approximately constant size on
> > disk?
> > > > > > > > (Failing
> > > > > > > > > that perhaps a delete statement
> > that
> > > > > > would
> > > > > > > > just
> > > > > > > > > have it maintain a constant #
> of
> > > > records?
> > > > > > > > > ...maybe this would be much
> > simpler?)
> > > > > > > > >
> > > > > > > > > --- Dan Greene wrote:
> > > > > > > > > > cronjob a sql script that
> runs
> > a
> > > > delete
> > > > > > > > > > statement for old jobs daily
> > > > > > > > > >
> > > > > > > > > > > --- Egor Egorov wrote:
> > > > > > > > > > > > Scott H wrote:
> > > > > > > > > > > >> Can't seem to find this
> > one in
> > > > the
> > > > > > > > manual
> > > > > > > > > > or
> > > > > > > > > > > >> archives - how do I
> > control a
> > > > db
> > > > > > to
> > > > > > > > > > maintain
> > > > > > > > > > > >> its size to an arbitrary
> > > > value,
> > > > > > say 20
> > > > > > > > GB?
> > > > > > > > > > I
> > > > > > > > > > > >> want to just rotate
> > records,
> > > > > > deleting
> > > > > > > > > > those
> > > > > > > > > > > >> that are oldest.
> > > > > > > > > > > >
> > > > > > > > > > > > You can't restrict size
> of
> > the
> > > > > > database
> > > > > > > > > > only
> > > > > > > > > > > > with MySQL, use disk
> > quotas.
> > > > > > > > > > >
> > > > > > > > > > > No!  That would just stop
> > mysql
> > > > right
> > > > > > in
> > > > > > > > its
> > > > > > > > > > > tracks (so to speak...)
> when
> > it
> > > > got
> > > > > > too
> > > > > > > > > > large.
> > > > > > > > > > > But I want old records
> > sloughed
> > > > off
> > > > > > and
> > > > > > > > the
> > > > > > > > > > db to
> > > > > > > > > > > continue running.  (This is
> > for a
> > > > > > central
> > > > > > > > > > syslog
> > > > > > > > > > > box.)
> > > 
> > > 
> > > 
> > > __________________________________
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> 
> 
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